二分法求方程根

/* *方程：2*x*x*x - 4*x*x + 3*x - 6 = 0; */#include <iostream>#include <cmath>using namespace std;double f(double x);int main(void){double x1 = -10, x2 = 10, x;    while(fabs(x1-x2)>=1e-6){x = (x1+x2)/2;if(f(x)*f(x1)<0){x2 = x;}else{x1 = x;}}cout << x1 << endl;}double f(double x){return 2*x*x*x - 4*x*x + 3*x - 6;}