正则表达式匹配括号外的符号

[\\?!/\\.,\\s]+(?=[^\\)]*(\\(|$))

将括号外的?!/.,和空格（连续多个时同时）匹配

如

String string1 = "sdfsdf sdlfksd sdf,fsdf&sdf(s:1,g:1) sdfsd sdf! ? .  sdfl asdf ";String[] str = string1.split("[\\?!/\\.,\\s]+(?=[^\\)]*(\\(|$))");for(String s:str){System.out.println(s);}

 

结果:

sdfsdfsdlfksdsdffsdf&sdf(s:1,g:1)sdfsdsdfsdflasdf