简单题 ( hdu2114 )

         直接运用求和公式  简单

         代码:

#include <stdio.h>#include <math.h>#include <string.h>int main(){    __int64 n,m,ans;    while(scanf("%I64d",&n)!=EOF)    {               m=n+1;               if(n%2==0)                  n=n/2;               else                  m=m/2;               ans= ( ((n%10000)*(m%10000)%10000 ) *  ((n%10000)*(m%10000)%10000))%10000;              printf("%04I64d\n",ans);    }    return 0;}

  输出格式可以注意下下!!