hdu 1673

Optimal Parking

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 957    Accepted Submission(s): 839

Problem Description

When shopping on Long Street, Michael usually parks his car at some random location, and then walks to the stores he needs.
Can you help Michael choose a place to park which minimises the distance he needs to walk on his shopping round?
Long Street is a straight line, where all positions are integer.
You pay for parking in a specific slot, which is an integer position on Long Street. Michael does not want to pay for more than one parking though. He is very strong, and does not mind carrying all the bags around.

 

Input

The first line of input gives the number of test cases, 1 <= t <= 100. There are two lines for each test case. The first gives the number of stores Michael wants to visit, 1 <= n <= 20, and the second gives their n integer positions on Long Street, 0 <= xi <= 99.

 

Output

Output for each test case a line with the minimal distance Michael must walk given optimal parking.

 

Sample Input

2424 13 89 3767 30 41 14 39 42

 

Sample Output

15270

 

Source

2008 “Insigma International Cup” Zhejiang Collegiate Programming Contest - Warm Up（3）

 

Recommend

lcy

 

//题目意思就是从某个停车位出发购物，最终回到最初停车位所走的最短距离//将停车位排序，然后相邻相减，就是最短距离#include <iostream>#include <algorithm>using namespace std;int main(){int t, n, dis, a[21], i;scanf("%d", &t);while (t--){scanf("%d", &n);for(i = 0; i < n; i++)scanf("%d", &a[i]);sort(a, a+n);dis = abs(a[n-1] - a[0]);for(i = 1; i < n; i++)dis += abs(a[i] - a[i-1]);printf("%d\n", dis);}return 0;}