poj 3299

来源：互联网发布：add鼓音源下载mac 编辑：程序博客网时间：2024/05/04 12:05
用小题目试用了一下emacs这种神器。。。
#include <cstdio>#include <iostream>#include <cstring>#include <cstdlib>#include <set>#include <vector>#include <map>#include <list>#include <iomanip>#include <algorithm>#include <deque>#include <string>#include <cctype>g++#include <cmath>using namespace std;                                              ///宏定义const int INF = 20000000;const int maxn = 2000;///全局变量 全局函数double T, D, H;//温度，露点， 湿度///int main(){         ///    while(1)    {        T = D = H = 200;        char temp;        while(scanf("%c", &temp) && temp == '\n');        if(temp == 'E')            break;        double tmp;        scanf("%lf", &tmp);        if(temp == 'T')            T = tmp;        else if(temp == 'D')            D = tmp;        else if(temp == 'H')            H = tmp;        while(scanf("%c", &temp) && temp == ' ');        //      scanf("%c", &temp);        scanf("%lf", &tmp);        if(temp == 'T')            T = tmp;        else if(temp == 'D')            D = tmp;        else if(temp == 'H')            H = tmp;        if(T == 200)        {         T = H - 0.5555*(6.11*exp(5417.7530*(1/273.16-1/(D + 273.16)))-10);          }        else if(D == 200)        {             D = 1/((1/273.16)-((log((((H - T)/0.5555)+10.0)/6.11))/5417.7530))-273.16;        }        else if(H == 200)        {             H = T + 0.5555 *(6.11 * exp(5417.7530*(1/273.16-1/(D + 273.16))) - 10);        }        printf("T %.1f D %.1f\ H %.1f\n", T, D, H);    }///结束    return 0;}