杭电 ACM 1.2.5
来源:互联网 发布:python写网络扫描器 编辑:程序博客网 时间:2024/05/02 04:04
ASCII
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)Total Submission(s): 1976 Accepted Submission(s): 863Problem Description
Since all we know the ASCII code, your job is simple: input numbers and output corresponding messages.
Input
The first line contains one integer T (1<=T<=1000).
The input will contain T positive integers separated by whitespaces (spaces, newlines, TABs).
The integers will be no less than 32.
The input will contain T positive integers separated by whitespaces (spaces, newlines, TABs).
The integers will be no less than 32.
Output
Output the corresponding message in just one line.
Warning: no extra characters are allowed.
Warning: no extra characters are allowed.
Sample Input
1372 101 108 108 111 4432 119 111 114 108 100 33
Sample Output
Hello, world!
Source
“光庭杯”第五届华中北区程序设计邀请赛 暨 WHU第八届程序设计竞赛
Recommend
lcy
这题没什么说的;
代码:
#include<stdio.h>
#include<malloc.h>
int main(void)
{
int t;
int i;
int *a;
while(scanf("%d", &t) != EOF && t != 0)
{
getchar();
a = (int*)malloc(sizeof(int) * t);
for(i = 0;i < t;i++)
{
scanf("%d", &a[i]);
getchar();
}
for(i = 0;i < t;i++)
{
printf("%c", a[i]);
}
free(a);
}
return 0;
}
- 杭电 ACM 1.2.5
- 杭电 acm steps1.1.2
- 杭电 ACM 1.2.2
- 杭电 ACM 1.2.1
- 杭电 ACM 1.2.4
- 杭电 ACM 1.2.3
- 杭电 ACM 1.2.6
- 杭电 ACM 1.2.7
- 杭电 ACM 1.2.8
- 杭电 ACM 1.3.5
- 杭电acm 1.2.7 GPA
- 杭电 acm 1.2.8 Vowel Counting
- 杭电ACM ASCII 1.2.7
- 杭电ACM 1.2.4 GPA
- 杭电oj-acm steps-1.2
- 杭电ACM 1003
- 杭电 ACM 2016
- 杭电acm 1010
- 计算今天的凌晨时间
- 有关firefox不响应window.event的解决办法
- SVN更改登录用户
- VS与Win7共舞:系统服务的Session 0隔离
- 黑盒测试用例设计模式-正交试验(上)
- 杭电 ACM 1.2.5
- 优化JVM参数提高eclipse运行速度
- iOS APP开发控件大盘点
- Hdu 2602 Bone Collector
- Perl lib path
- Python加载包脚本示例
- VS与Win7共舞:UAC惹祸 如何进行安装程序检测
- Linux C中attribute机制
- 黑马程序员_对象的序列化