hdu 1985

Conversions

Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1124    Accepted Submission(s): 647

Problem Description

Conversion between the metric and English measurement systems is relatively simple. Often, it involves either multiplying or dividing by a constant. You must write a program that converts between the following units:

 

Input

The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of a single line of input containing a floating point (double precision) number, a space and the unit specification for the measurement to be converted. The unit specification is one of kg, lb, l, or g referring to kilograms, pounds, liters and gallons respectively.

 

Output

For each dataset, you should generate one line of output with the following values: The dataset number as a decimal integer (start counting at one), a space, and the appropriately converted value rounded to 4 decimal places, a space and the unit specification for the converted value.

 

Sample Input

51 kg2 l7 lb3.5 g0 l

 

Sample Output

1 2.2046 lb2 0.5284 g3 3.1752 kg4 13.2489 l5 0.0000 g

 

Source

2008 “Shun Yu Cup” Zhejiang Collegiate Programming Contest - Warm Up（1）

 

Recommend

linle

 

//该题就是简单的单位换算#include <stdio.h>#include <string.h>int main(){int n, i;double in;char c[3];scanf("%d", &n);for (i = 1; i <= n; i++){scanf("%lf%s", &in, c);if (strcmp(c, "kg") == 0)printf("%d %.4lf lb\n", i, in*2.2046);else if (strcmp(c, "lb") == 0)printf("%d %.4lf kg\n", i, in*0.4536);else if (strcmp(c, "l") == 0)printf("%d %.4lf g\n", i, in*0.2642);else if (strcmp(c, "g") == 0)printf("%d %.4lf l\n", i, in*3.7854);}return 0;}