HDU 1555How many days?

How many days?

Time Limit: 3000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 3416 Accepted Submission(s): 2034

Problem Description

8600的手机每天消费1元，每消费K元就可以获赠1元，一开始8600有M元，问最多可以用多少天？

Input

输入包括多个测试实例.每个测试实例包括2个整数M, k，（2 <= k <= M <= 1000).M = 0, k = 0代表输入结束.

Output

对于每个测试实例输出一个整数，表示M元可以用的天数。

Sample Input

2 24 30 0

Sample Output

35

Author

8600

Source

HDU 2006-12 Programming Contest

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LL

#include<stdio.h>int main(){  int m,k,sum,t;  while(scanf("%d%d",&m,&k)!=EOF)  {      if(m==0&&k==0)          break;      sum=m;t=0;      while(sum)      {          sum--;          t++;          if(t%k==0)              sum+=1;      }      printf("%d\n",t);  }  return 0;}