百练 2887 能被3，5，7整除的数

题目链接：http://bailian.openjudge.cn/practice/2887

# include <stdio.h>int main(){int n,i,a[3]={3,5,7},c;while(scanf("%d",&n)!=EOF){c=0;for(i=0;i<3;i++)if(n%a[i]==0)c++;if(c==0)printf("n\n");if(c==1)for(i=0;i<3;i++)if(n%a[i]==0)printf("%d\n",a[i]);if(c==2){for(i=0;i<3;i++)if(n%a[i]==0)printf("%d ",a[i]);printf("\n");}if(c==3)printf("3 5 7\n");}return 0;}