两个方程式求解

#include <stdio.h>#include "math.h"int main(int argc, char *argv[]){  //ax2+bx+c=0方程根 abc键盘输入  //b2-4ac>0  //公式 x1=(-b+sqrt(b2-4ac))/2a   float a,b,c;  float x1,x2, disc;    printf("int put the fangchengshi about a,b,c:");  scanf("%d,%d,%d",&a,&b,&c);  disc= b*b-4*a*c;  printf("%f\n",disc);  if(disc>=0)     { x1=(-b+sqrt(disc))/(2*a);     x2=(-b-sqrt(disc))/(2*a);     printf("x1=%d\nx2=%d\n",x1,x2); }      else          printf("the problem is no answer!!");  return 0;}/*int put the fangchengshi about a,b,c:1,2,10.000000x1=0x2=-1074790400请按任意键继续. . .*/