杭电OJ——1228 A+B

A + B

Problem Description

读入两个小于100的正整数A和B,计算A+B.
需要注意的是:A和B的每一位数字由对应的英文单词给出.

 

Input

测试输入包含若干测试用例,每个测试用例占一行,格式为"A + B =",相邻两字符串有一个空格间隔.当A和B同时为0时输入结束,相应的结果不要输出. 

 

Output

对每个测试用例输出1行,即A+B的值.

 

Sample Input

one + two =three four + five six =zero seven + eight nine =zero + zero =

 

Sample Output

39096

 

Source

浙大计算机研究生复试上机考试-2005年

 

Recommend

JGShining

代码如下：

#include<stdio.h>#include<stdlib.h>#include<string.h>int covert(char s[]){  if(!strcmp(s,"zero")) return 0; else if(!strcmp(s,"one")) return 1; else if(!strcmp(s,"two")) return 2; else if(!strcmp(s,"three")) return 3; else if(!strcmp(s,"four")) return 4; else if(!strcmp(s,"five")) return 5; else if(!strcmp(s,"six")) return 6; else if(!strcmp(s,"seven")) return 7; else if(!strcmp(s,"eight")) return 8; else if(!strcmp(s,"nine")) return 9; return 0;}int main(){ int a,b; char s[6]; while(1) {  for(a=0,scanf("%s",s);s[0]!='+';scanf("%s",s))   a=a*10+covert(s);  for(b=0,scanf("%s",s);s[0]!='=';scanf("%s",s))   b=b*10+covert(s);  if(a+b==0) return 0;  printf("%d\n",a+b); } system("pause"); return 0;}