九度1003 A+B

/********************************* *    日期：2012-6-23 *    作者：SJF0115 *    题号: 九度1003 *    题目：A+B *    结果：AC *    题意： *    总结：**********************************/#include<stdio.h>#include<string>long int N,M;long int sequence1[1000001];long int sequence2[1000001];int main(){    while(scanf("%ld",&N)!=EOF)    {   int i,j;int medianNum,median,num = 0;        for(i = 0;i<N;i++){scanf("%ld",&sequence1[i]);}scanf("%ld",&M);medianNum = ((N+M)%2==0)?(N+M)/2:(N+M)/2+1;for(i = 0;i<M;i++){scanf("%ld",&sequence2[i]);}for(i = 0,j = 0;i<N&&j<M;){num++;if(sequence1[i]<sequence2[j]){if(num == medianNum){median = sequence1[i];break;}i++;}else{if(num == medianNum){median = sequence2[j];break;}j++;}}if(num  == medianNum){printf("%d\n",median);}else{if(i < N){printf("%d\n",sequence1[i+medianNum - num - 1]);}else{printf("%d\n",sequence2[j+medianNum - num - 1]);}}    }    return 0;}