zoj 1394 Polar Explorer

Using this information along with how much gasoline is available for your planet-rover (which gets a measley 5 miles per gallon), you have to determine if you can possibly get to the crash site and back without running out of fuel.

 

 

注意题目所说的是来回车程，而且所给的角不一定就是车所走的路线对应的角。。还需判断若角度大于180度，则应该选择小于180的角走。。

#include<iostream>#include<string.h>using namespace std;#define PI 3.14159 int main(){int r,y,o,v=5;char s[10];float l;while(cin>>s){if(strcmp(s,"START")==NULL){cin>>r>>y>>o>>s;if(o>180)o=360-o;l=o*1.0/360*2*PI*r;if(v*y>=2*l)cout<<"YES "<<(int)(v*y-2*l)/v<<endl;elsecout<<"NO "<<v*y<<endl;}elseif(strcmp(s,"ENDOFINPUT")==NULL)break;}return 0;}