如何在不同编程语言中获取现在的Unix时间戳(Unix timestamp)

如何在不同编程语言中获取现在的Unix时间戳(Unix timestamp)？

先上代码进行java时间转换成unix timestamp

import java.text.DateFormat;import java.text.ParseException;import java.text.SimpleDateFormat;import java.util.Date;/** * @author kongqz [e-mail] * @version 创建时间：2013-2-19 上午10:21:47 */public class TestUnixTime {public static void main(String[] args) throws ParseException{DateFormat df=new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");//1361325960long epoch = df.parse("2013-02-20 10:06:00").getTime();System.out.println("should be 1361325960 ："+epoch);Date d=new Date();String t=df.format(d);epoch=df.parse(t).getTime()/1000;System.out.println("t is ："+t+",unix stamp is "+epoch); }}

JavatimeJavaScriptMath.round(new Date().getTime()/1000)
getTime()返回数值的单位是毫秒Microsoft .NET / C#epoch = (DateTime.Now.ToUniversalTime().Ticks - 621355968000000000) / 10000000MySQLSELECT unix_timestamp(now())PerltimePHPtime()PostgreSQLSELECT extract(epoch FROM now())Python先 import time 然后 time.time()Ruby获取Unix时间戳：Time.now 或 Time.new
显示Unix时间戳：Time.now.to_iSQL ServerSELECT DATEDIFF(s, '1970-01-01 00:00:00', GETUTCDATE())Unix / Linuxdate +%sVBScript / ASPDateDiff("s", "01/01/1970 00:00:00", Now())其他操作系统
(如果Perl被安装在系统中)命令行状态：perl -e "print time"

如何在不同编程语言中实现Unix时间戳(Unix timestamp) → 普通时间？

JavaString date = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").format(new java.util.Date(Unix timestamp * 1000)).getTime();JavaScript先 var unixTimestamp = new Date(Unix timestamp * 1000)然后 commonTime = unixTimestamp.toLocaleString()Linuxdate -d @Unix timestampMySQLfrom_unixtime(Unix timestamp)Perl先 my $time = Unix timestamp 然后 my ($sec, $min, $hour, $day, $month, $year) = (localtime($time))[0,1,2,3,4,5,6]PHPdate('r', Unix timestamp)PostgreSQLSELECT TIMESTAMP WITH TIME ZONE 'epoch' + Unix timestamp) * INTERVAL '1 second';Python先 import time 然后 time.gmtime(Unix timestamp)RubyTime.at(Unix timestamp)SQL ServerDATEADD(s, Unix timestamp, '1970-01-01 00:00:00')VBScript / ASPDateAdd("s", Unix timestamp, "01/01/1970 00:00:00")其他操作系统
(如果Perl被安装在系统中)命令行状态：perl -e "print scalar(localtime(Unix timestamp))"

如何在不同编程语言中实现普通时间 → Unix时间戳(Unix timestamp)？

Javalong epoch = new java.text.SimpleDateFormat("dd/MM/yyyy HH:mm:ss").parse("01/01/1970 01:00:00");JavaScriptvar commonTime = new Date(Date.UTC(year, month - 1,day,hour,minute,second))MySQLSELECT unix_timestamp(time)
时间格式: YYYY-MM-DD HH:MM:SS 或 YYMMDD 或 YYYYMMDDPerl先 use Time::Local 然后 my $time = timelocal($sec, $min, $hour, $day, $month, $year);PHPmktime(hour, minute, second, day,month,year)PostgreSQLSELECT extract(epoch FROM date('YYYY-MM-DD HH:MM:SS'));Python先 import time 然后 int(time.mktime(time.strptime('YYYY-MM-DD HH:MM:SS', '%Y-%m-%d %H:%M:%S')))RubyTime.local(year, month, day, hour,minute,second)SQL ServerSELECT DATEDIFF(s, '1970-01-01 00:00:00', time)Unix / Linuxdate +%s -d"Jan 1, 1970 00:00:01"VBScript / ASPDateDiff("s", "01/01/1970 00:00:00", time)