[RTT例程练习] 2.3 信号量-检测按键(同步) -(信号量互斥)
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这里,使用信号量来同步两个线程。
简单来说,线程每隔一定的时间扫描按键。一旦其检测到有效的按键,便release 信号量,使得线程2 从挂起进入 运行态,向串口打印按键信息。
这样,便实现了两个线程的同步。
程序:
#include <rtthread.h>#include "stm32f10x.h"#define KEY_PORT GPIOB#define KEY_PIN (GPIO_Pin_0 | GPIO_Pin_1)#define KEY_CLOCK RCC_AHB1Periph_GPIOBvoid rt_init_thread_entry(void *parameter){GPIO_InitTypeDef GPIO_InitStructure;//开启PB0时钟RCC_APB2PeriphClockCmd(RCC_APB2Periph_GPIOB,ENABLE);GPIO_InitStructure.GPIO_Pin = GPIO_Pin_0;GPIO_InitStructure.GPIO_Speed = GPIO_Speed_10MHz;GPIO_InitStructure.GPIO_Mode = GPIO_Mode_IPU;GPIO_Init(GPIOB,&GPIO_InitStructure);} static rt_uint8_t thread1_stack[1024];struct rt_thread thread1;static int key;static struct rt_semaphore sem;static void rt_thread_entry1(void *parameter){ int temp; while (1) { key = GPIO_ReadInputData(KEY_PORT); if (key & KEY_PIN) { temp = key; rt_thread_delay(RT_TICK_PER_SECOND / 50); key = GPIO_ReadInputData(KEY_PORT); if (key == temp); rt_sem_release(&sem); } rt_thread_delay(RT_TICK_PER_SECOND / 10); }}static rt_uint8_t thread2_stack[1024];struct rt_thread thread2;//static int key;static void rt_thread_entry2(void *parameter){ while (1) { rt_sem_take(&sem, RT_WAITING_FOREVER); if (key & KEY_PIN) { rt_kprintf("some keys has been pressed: %x\n", key); } }}int rt_application_init(){ rt_thread_t init_thread; rt_err_t result; result = rt_sem_init(&sem, "sem", 0, RT_IPC_FLAG_FIFO); if (result != RT_EOK) { rt_kprintf("error, init sem failed!\n"); return 0; } init_thread = rt_thread_create("init", rt_init_thread_entry, RT_NULL, 2048, 8, 20); if (init_thread != RT_NULL) rt_thread_startup(init_thread); /* init thread1 */ rt_thread_init(&thread1, "keyp", // producer rt_thread_entry1, RT_NULL, &thread1_stack[0], sizeof(thread1_stack), 11, 25); rt_thread_startup(&thread1); rt_thread_init(&thread2, "keyc", // consumer rt_thread_entry2, RT_NULL, &thread2_stack[0], sizeof(thread2_stack), 11, 24); rt_thread_startup(&thread2); return 0;}
结果为:
some keys has been pressed : 40some keys has been pressed : 80
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