hdoj 2700 (奇偶校验)（水题）

#include<iostream>#include<stdio.h>#include<math.h>#include<string>using namespace std;char inputstr[50];int main(){//freopen("in.txt","r",stdin);while(scanf("%s",inputstr)){//如果输入#代表结束if(inputstr[0]=='#'){return 0;}//计算奇偶int length=strlen(inputstr);int sum=0;int i=0;for(i=0;i<length-1;i++){sum+=inputstr[i]-'0';}//输出for(i=0;i<length-1;i++){cout<<inputstr[i];}//if(inputstr[length-1]=='e')cout<<sum%2<<endl;elsecout<<1-sum%2<<endl;}cout<<""<<endl;}