【shell】切分字符串

方法1：用awk切分

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dbs="idigger,idiggersem,sony,mso"
dbarr=`echo $dbs | awk -F"," '{print $0}' | sed "s/,/ /g"`
for db in $dbarr
do
    echo $db
done
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运行结果如下：

$ sh awk_divide.sh
idigger
idiggersem
sony
mso

方法2：用shell切分

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dbs="idigger,idiggersem,sony,mso"
dbarr=(${dbs//,/ })             #将字符串中，替换成空格

dbnum=${#dbarr[@]}
echo $dbnum
for db in ${dbarr[@]}
do
    echo $db
done
-------------------------------------------------

运行结果如下：

$ sh shell_divide.sh
4
idigger
idiggersem
sony
mso