用结构体计算一天在一年中的天数

#include "stdafx.h"#include"iostream"using namespace std;struct Date{int year;int month;int day;};int main(){int sum;sum=0;struct Date date;int a[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};cin>>date.year;cin>>date.month;cin>>date.day;    if(date.year%4==0&&date.year%100!=0 || date.year%400==0){if(date.month>2)      date.day=date.day+1;elsedate.day=date.day ;for(int i=1;i<date.month;i++){sum=sum+a[i];}sum=sum+date.day;cout<<sum<<endl;}else{date.day=date.day;        for(int i=1;i<date.month;i++){sum=sum+a[i];}sum=sum+date.day;cout<<"";    cout<<sum<<endl;}return 0;}