Asp.Net MVC 在后台获取PartialView、View文件生成的字符串

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在Asp.net MVC的实际开发中，有时需要在后台代码中获取某个View 或者 PartialView 生成的字符串，示例如下：

1. 将View文件输出为字符串：

　　　　　 /// <summary>         /// 将View输出为字符串         /// </summary>         /// <param name="controller">Controller实例</param>         /// <param name="viewName">如果view文件在当前Controller目录下，则直接输入文件名(例:Toolbar)；否则,从根路径开始指定(例：~/Views/User/Toolbar.cshtml)</param>         /// <param name="masterName">母板页文件名</param>         /// <returns>字符串</returns>         protected static string RenderViewToString(Controller controller, string viewName, string masterName)         {             IView view = ViewEngines.Engines.FindView(controller.ControllerContext, viewName, masterName).View;             using (StringWriter writer = new StringWriter())             {                 ViewContext viewContext = new ViewContext(controller.ControllerContext, view, controller.ViewData, controller.TempData, writer);                 viewContext.View.Render(viewContext, writer);                 return writer.ToString();             }         }

2.将PartialView文件输出为字符串

 1　　　　　 /// <summary> 2         /// 将PartialView输出为字符串 3         /// </summary> 4         /// <param name="controller">Controller实例</param> 5         /// <param name="viewName">如果PartialView文件在当前Controller目录下，则直接输入文件名(例:Toolbar)；否则,从根路径开始指定(例：~/Views/User/Toolbar.cshtml)</param> 6         /// <param name="model">构造页面所需的的实体参数</param> 7         /// <returns>字符串</returns> 8         public static string RenderPartialViewToString(Controller controller, string viewName,object model) 9         {10             IView view = ViewEngines.Engines.FindPartialView(controller.ControllerContext, viewName).View;11             controller.ViewData.Model = model;12             using (StringWriter writer = new StringWriter())13             {14                 ViewContext viewContext = new ViewContext(controller.ControllerContext, view, controller.ViewData, controller.TempData, writer);15                 viewContext.View.Render(viewContext, writer);16                 return writer.ToString();17             }18         }