将浮点数类型的number转换成英语的表达方式

最近在做一个信息管理系统,管理系统有个发票模块,这个模块要求输出Double类型的英文表达方式,程序如下:

public class ConvertNumToStr {public static String parse(Object x) {if (x != null) {return parse(x + "");} else {return "";}}private static String parse(String x) {int z = x.indexOf("."); // 取小数点位置String lstr = "", rstr = "";if (z > -1) { // 看是否有小数，如果有，则分别取左边和右边lstr = x.substring(0, z);rstr = x.substring(z + 1);} else// 否则就是全部lstr = x;String lstrrev = reverse(lstr); // 对左边的字串取反String[] a = new String [5]; // 定义5个字串变量来存放解析出来的叁位一组的字串switch (lstrrev.length() % 3) {case 1:lstrrev += "00";break;case 2:lstrrev += "0";break;}String lm = ""; // 用来存放转换後的整数部分for (int i = 0; i < lstrrev.length() / 3; i++) {a[i] = reverse(lstrrev.substring(3 * i, 3 * i + 3)); // 截取第一个叁位if (!a[i].equals("000")) { // 用来避免这种情况：1000000 = one million                       // thousand onlyif (i != 0)lm = transThree(a[i]) + " " + parseMore(String.valueOf(i)) + " " + lm; // 加:                                                                       // thousand、million、billionelselm = transThree(a[i]); // 防止i=0时， 在多加两个空格.} elselm += transThree(a[i]);}String xs = ""; // 用来存放转换後小数部分if (z > -1)xs = "AND CENTS " + transTwo(rstr) + " "; // 小数部分存在时转换小数return lm.trim() + " " + xs + "ONLY";}private static String parseFirst(String s) {String[] a = new String [] { "", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX", "SEVEN", "EIGHT", "NINE"};return a[Integer.parseInt(s.substring(s.length() - 1))];}private static String parseTeen(String s) {String[] a = new String [] { "TEN", "ELEVEN", "TWELEVE", "THIRTEEN", "FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN", "NINETEEN"};return a[Integer.parseInt(s) - 10];}private static String parseTen(String s) {String[] a = new String [] { "TEN", "TWENTY", "THIRTY", "FORTY", "FIFTY", "SIXTY", "SEVENTY", "EIGHTY", "NINETY"};return a[Integer.parseInt(s.substring(0, 1)) - 1];}// 两位private static String transTwo(String s) {String value = "";// 判断位数if (s.length() > 2)s = s.substring(0, 2);else if (s.length() < 2)s = "0" + s;if (s.startsWith("0")) // 07 - seven 是否小於10value = parseFirst(s);else if (s.startsWith("1")) // 17 seventeen 是否在10和20之间value = parseTeen(s);else if (s.endsWith("0")) // 是否在10与100之间的能被10整除的数value = parseTen(s);elsevalue = parseTen(s) + " " + parseFirst(s);return value;}private static String parseMore(String s) {String[] a = new String [] { "", "THOUSAND", "MILLION", "BILLION"};return a[Integer.parseInt(s)];}// 制作叁位的数// s.length = 3private static String transThree(String s) {String value = "";if (s.startsWith("0")) // 是否小於100value = transTwo(s.substring(1));else if (s.substring(1).equals("00")) // 是否被100整除value = parseFirst(s.substring(0, 1)) + " HUNDRED";elsevalue = parseFirst(s.substring(0, 1)) + " HUNDRED AND " + transTwo(s.substring(1));return value;}private static String reverse(String s) {char[] aChr = s.toCharArray();StringBuffer tmp = new StringBuffer();for (int i = aChr.length - 1; i >= 0; i--) {tmp.append(aChr[i]);}return tmp.toString();}public static void main(String[] args) {System.out.println("*** " + ConvertNumToStr.parse("100.23"));System.out.println("*** " + ConvertNumToStr.parse("2100.00"));}}