shell脚本报错:-bash: xxx: /bin/sh^M: bad interpreter: No such fi
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今天写了一个shell脚本,然后在执行的时候报错,脚本内容很简单,仅供测试:
Shell代码:
- #!/bin/sh
- echo "test shell "
具体报错信息如下:
Shell代码:
- [root@localhost test]# ./test.sh
- -bash: ./test.sh: /bin/sh^M: bad interpreter: No such file or directory
由于之前自己对shell不太熟悉,找同事沟通了后了解了原委,主要原因是test.sh是我在windows下编辑然后上传到linux系统里执行的。.sh文件的格式为dos格式。而linux只能执行格式为unix格式的脚本。
我们可以通过vi编辑器来查看文件的format格式。步骤如下:
1.首先用vi命令打开文件
Shell代码 :
- [root@localhost test]# vi test.sh
2.在vi命令模式中使用 :set ff 命令
可以看到改文件的格式为dos
3.修改文件format为unix
方法一:使用vi修改文件format
命令:set ff=unix
执行完后再通过set ff命令查看文件格式,结果如下:
方法二:直接使用dos2unix命令修改
Shell代码:
- [root@localhost test]# dos2unix test.sh
- dos2unix: converting file test.sh to UNIX format ...
修改完后再次执行./test.sh,执行正确:
原文链接:http://www.software8.co/wzjs/czxt/3561.html
Shell代码:
- [root@localhost test]# ./test.sh
- test shell
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