应该也是模拟_题目1146:Flipping Pancake

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题目给的测试数据能过,但一提交却变成RA

貌似问题是出在第28行和第31行,因为我一注释掉它们就变成WA

可能是在特定的输入下它们会导致下标越界之类的错误,但就是想不通究竟是啥情况,SOS~

这道题原本没那么多提交的,全是给我的RA刷的 T_T

 

时间限制:1 秒

内存限制:32 兆

特殊判题:

提交:110

解决:41

 

题目描述:

    We start with a stack n of pancakes of distinct sizes. The problem is to convert the stack to one in which the pancakes are in size order with the smallest on the top and the largest on the bottom. To do this, we are allowed to flip the top k pancakes over as a unit (so the k-th pancake is now on top and the pancake previously on top is now in the k-th position).

    For example: This problem is to write a program, which finds a sequence of at most (2n - 3) flips, which converts a given stack of pancakes to a sorted stack. 

输入:

    Each line of the input gives a separate data set as a sequence of numbers separated by spaces. The first number on each line gives the number, N, of pancakes in the data set. The input ends when N is 0 (zero) with no other data on the line. The remainder of the data set are the numbers 1 through N in some order giving the initial pancake stack.

    The numbers indicate the relative sizes of the pancakes. N will be, at most, 30. 

输出:

     For each data set, the output is a single-space separated sequence of numbers on a line. The first number on each line, K, gives the number of flips required to sort the pancakes. This number is followed by a sequence of K numbers, each of which gives the number of pancakes to flip on the corresponding sorting step. There may be several correct solutions for some datasets. For instance 3 3 2 3 is also a solution to the first problem below. 

样例输入:
3 1 3 25 4 3 2 5 10
样例输出:
3 2 3 2 3 3 4 5 
来源:
2009年北京大学计算机研究生机试真题
答疑:
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可怜的被创造出来却没法运行的代码的清单 T_T

 

#include <stdio.h>#define MAX 100 int e[MAX];int ans[2*MAX] = {0};int n;void reverse(int i){    if(i>0) ans[++ans[0]] = i+1;    int temp;    int j=0;    while(i > j){        temp = e[i];        e[i--] = e[j];        e[j++] = temp;}} int main(){    while(scanf("%d",&n),n){        for(int i=0; i<n; i++) scanf("%d",e+i);        for(int i=1; i<n; i++){            if(e[i] > e[i-1]) continue;            if(e[i] < e[0]){                reverse(i-1);                reverse(i);}            else{                reverse(i);                int j=0;                while(j<n-1 && e[j+1] > e[0]) j++;                reverse(j);                reverse(i);                i = i-j+1;}}        for(int i=0;i<=ans[0];i++){            printf("%d ",ans[i]);}        printf("\n");        ans[0]=0;}    return 0;}/**************************************************************    Problem: 1146    User: denallo    Language: C    Result: Runtime Error****************************************************************/