Python urlparse总结

res = urlparse.urlparse(url,scheme,allow_fragments)
返回一个6-tuple，类型是ParseResult(scheme, netloc, path, params, query, fragment)
ParseResult类还有几个常用方法：
res.username
res.password
res.hostname
res.port
res.geturl()


urlparse.urlunparse(data)
返回一个string
data必须是six-item iterable


res = urlparse.urlsplit(url,scheme,allow_fragments)
返回一个5-tuple，类型是.SplitResult(scheme, netloc, path, query, fragment)
这里的path相当于urlparse的path+params,具体见例子


urlparse.urlunsplit(data)
返回一个string
data必须是five-item iterable


urlparse.urljoin(base, url, allow_fragments)

这个函数比较复杂，不同的数据得出的结果大不一样，而且容易出现错误，不建议用这个函数，详见下面几个例子

'''Created on 2013-4-15@author: xkey'''import urlparseurl = "https://www.google.com.hk:8080/home/search;12432?newwi.1.9.serpuc#1234"r = urlparse.urlparse(url)print rprint r.port,r.hostnameprint r.geturl()r = urlparse.urlsplit(url)print rparts = ["http","www.facebook.com","/home/email","132","parts","md5=?"]print urlparse.urlunparse(parts)print urlparse.urlunsplit(parts[0:5])base = "http://baidu.com/home"url = "index.html"print urlparse.urljoin(base, url)base = "http://baidu.com/home/action.jsp"url = "index.html"print urlparse.urljoin(base, url)base = "http://baidu.com/home/action.jsp"url = "/index.html"print urlparse.urljoin(base, url)base = "http://baidu.com/home/action.jsp"url = "../../index.html"print urlparse.urljoin(base, url)

输出结果：

ParseResult(scheme='https', netloc='www.google.com.hk:8080', path='/home/search', params='12432', query='newwi.1.9.serpuc', fragment='1234')8080 www.google.com.hkhttps://www.google.com.hk:8080/home/search;12432?newwi.1.9.serpuc#1234SplitResult(scheme='https', netloc='www.google.com.hk:8080', path='/home/search;12432', query='newwi.1.9.serpuc', fragment='1234')http://www.facebook.com/home/email;132?parts#md5=?http://www.facebook.com/home/email?132#partshttp://baidu.com/index.htmlhttp://baidu.com/home/index.htmlhttp://baidu.com/index.htmlhttp://baidu.com/../index.html

参照官方文档2.7.4：http://docs.python.org/2/library/urlparse.html