编程将二进制IP地址转换成十进制

/******************************************************************* Name: IP Address* Funcion: To convert binary numbers to decimal numbers* Input: 0000 0011 1000 0000 1111 1111 1111 1111* Output: 3.128.255.255**********************************************************************/#include<stdio.h>#include<stdlib.h>#include<string.h>#include<iostream>#include<assert.h>using namespace std;void convert(char input[],unsigned char output[])//这里的output必须为无符号型，否则必然出错{    int count = -1,i;    for( i = 0; i < 32; i++ )    {        if( i % 8 == 0 )        count++;        if( input[i] == '1' )        {            switch( i % 8 )            {                case 0:                output[count] += 128;                break;                case 1:                output[count] += 64;                break;                case 2:                output[count] += 32;                break;                case 3:                output[count] += 16;                break;                case 4:                output[count] += 8;                break;                case 5:                output[count] += 4;                break;                case 6:                output[count] += 2;                break;                case 7:                output[count] += 1;                break;                default:                break;            }        }    }}/************************************增加难度 输入和输出都有句点分割  输入输出均表示为点分形式************************************/void binaryStringToInt(char binary[],int *data){    int n=strlen(binary);    for(int i=0;i<n;i++)    {        *data+=(binary[i]-'0')<<n-i-1;   //记得要  -'0' 谨记    }}void test1(){    char i[]="11011";    int d=0;    binaryStringToInt(i,&d);    cout<<"d= "<<d<<endl;}int  IP_convert(char input[],char output[]){    assert(NULL!=input);    assert(NULL!=output);    int count=0;    char temp[50]={0};    //char *s=strtok(input, '.');  谨记：strtok second  parameter is "" instead of ''    char *s=strtok(input, ".");    if(s==NULL)    {        cout<<"input error"<<endl;        return -1;    }    while(s != NULL)    {        //cout<<s<<endl;        binaryStringToInt(s,&count);   //求二进制字符串对应的整数值        //cout<<"count= "<<count<<endl;        itoa(count,temp,10);  //将得到的数字转化为字符串        count=0;                //一定要记得count  清零        strcat(output,temp);   //连接到目的字符串        strcat(output,".");    // 每一段添加一个点，但是最后会多一个点        s = strtok(NULL, ".");   //继续分割元字符串    }    int i=0;    while(output[i]!='\0')i++;    output[--i]='\0';  //消除最后多余的句点    return 0;}void test(){    char input[32];    unsigned char output[4]={0};    gets(input);    convert(input,output);    printf( "%d.%d.%d.%d\n", output[0], output[1], output[2], output[3] );    cout<<"---------------------------------"<<endl;}int main(){    //test1();    char i[]="00001101.00001111.00000001.00001010";    char o[10]={0};    IP_convert(i,o);    puts(o);    return 0;}