POJ 2411 Mondriaan's Dream 贴砖块类状态压缩DP入门

来源:互联网 发布:sql拼接字符串 编辑:程序博客网 时间:2024/05/22 04:54
#include <cstdio>#include <cstring>#include <algorithm>using namespace std;#define LL long longint n, m;LL dp[13][2666];LL cnt;int x, M;void dfs(int y, int pre, int now) {if(y == m) {if(pre == M-1) {dp[x+1][now] += cnt;//printf("x = %d cnt = %d\n", x ,cnt);}return;}if(pre&(1<<y) && !(now&(1<<y)) ) {        if(y+1 < m) dfs(y+2, pre, now|(1<<y)|(1<<(y+1)));        dfs(y+1, pre, now);}if(!(pre&(1<<y)) && !(now&(1<<y)))dfs(y+1, pre|(1<<y), now|(1<<y));}int main() {int i, j;while( ~scanf("%d%d", &n, &m) && n && m) {memset(dp, 0, sizeof(dp));M = (1<<m);dp[0][M-1] = 1;for(i = 0; i < n; i++)for(j = 0; j < M; j++) if(dp[i][j]){cnt = dp[i][j]; x = i;//printf("i = %d j = %d\n", i, j);dfs(0, j, 0);}printf("%lld\n", dp[n][M-1]);}return 0;}