cv::Mat 的数据拷贝

来源：互联网发布：匹配声音软件是什么编辑：程序博客网时间：2024/06/09 19:35

今日做跟踪，每次要处理两帧图片，处理完要将curFrame复制给preFrame，然后再读一幅新图片。

以下测试了3种方式数据拷贝的效率，详见代码。

int main(int argc, char* argv[]){Mat preFrame;Mat curFrame;preFrame = imread("E:\\001.bmp");curFrame = imread("E:\\005.jpg");cout<<"========直接用swap=========\n";int64 st1,et1;st1 = cvGetTickCount();for (int i=0;i<1001;i++){swap(preFrame,curFrame);}et1 = cvGetTickCount(); printf("swap 1000 times cost: %f milliseconds\n\n", (et1-st1)/(double)cvGetTickFrequency()/1000.0); imshow("frame 1",preFrame);imshow("frame 2",curFrame);cvWaitKey(-1);cout<<"========通过第三者交换=========\n";Mat tmp;st1 = cvGetTickCount();for (int i=0;i<1001;i++){tmp = preFrame;preFrame = curFrame;curFrame = tmp;}et1 = cvGetTickCount(); printf("swap 1000 times cost: %f milliseconds\n\n", (et1-st1)/(double)cvGetTickFrequency()/1000.0); imshow("frame 1",preFrame);imshow("frame 2",curFrame);cvWaitKey(-1);cout<<"========强行拷贝=========\n";st1 = cvGetTickCount();for (int i=0;i<1001;i++){preFrame.copyTo(tmp);curFrame.copyTo(preFrame);tmp.copyTo(curFrame);}et1 = cvGetTickCount(); printf("swap 1000 times cost: %f milliseconds\n", (et1-st1)/(double)cvGetTickFrequency()/1000.0); imshow("frame 1",preFrame);imshow("frame 2",curFrame);cvWaitKey(-1);getchar();return 0;}

结果为：