Cuts the cake +面积相等

Cuts the cake

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1964    Accepted Submission(s): 1210

Problem Description

Ice cream took a bronze medal in the Beijing match. Liu sir is very very happy. So he buys a cake for them. kiki is a child who likes eating, so the task of cuting cake was given to kiki. kiki is also a mischievous child. She wants to cut the cake in a different way. This is introduced in the figure below.

But there is a difficult problem.which is how to make each preson get equally many cake. kiki is not good at match, so she wants you help her solve this problem.

 

Input

Input contains multiple test cases. Each line is a case.　Each case contains only one integer R which is the radius. The input is terminated with a R of 0.

 

Output

For each test case, you should printf two numbers r2 and r1 in a line, accurate up to 3 decimal places, separate them by one space.

 

Sample Input

10155250

 

Sample Output

5.774 8.1658.660 12.2472.887 4.08214.434 20.412

 

Author

☆RPG♀月野兔☆

 

Source

HDU 2007-11 Programming Contest_WarmUp
思路：由面积相等，可得r1,r2的计算公式
r1=(sqrt(3)*R)/3
r2=sqrt(R*R-r2*r2)

#include<iostream>#include<iomanip>#include<cmath>using namespace std;int main(){double R;while(cin>>R&&R){double r2=(sqrt(3)*R)/3;double r1=sqrt(R*R-r2*r2);cout<<fixed<<setprecision(3)<<r2<<" "<<fixed<<setprecision(3)<<r1<<endl;}return 0;}