HDU 1002

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A + B Problem II

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 154976 Accepted Submission(s): 29333

Problem Description

I have a very simple problem for you. Given two integers A and B, your job is to calculate the Sum of A + B.

Input

The first line of the input contains an integer T(1<=T<=20) which means the number of test cases. Then T lines follow, each line consists of two positive integers, A and B. Notice that the integers are very large, that means you should not process them by using 32-bit integer. You may assume the length of each integer will not exceed 1000.

Output

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

Sample Input

21 2112233445566778899 998877665544332211

Sample Output

Case 1:1 + 2 = 3Case 2:112233445566778899 + 998877665544332211 = 1111111111111111110

Author

Ignatius.L

package hdu1002;import java.util.*;import java.math.*;/** * 大数相加 */public class Main {public static void main(String[] args) {Scanner cin = new Scanner(System.in); // 定义一个输入流对象int t, flag = 0;BigInteger a, b, sum; // 定义大数t = cin.nextInt(); // 输入 twhile ((t--) != 0) {if ((flag++) != 0) // 设置标志，实现行之间的空格System.out.println();a = cin.nextBigInteger(); // 输入大数ab = cin.nextBigInteger(); // 输入大数bsum = a.add(b); // 两个大数相加System.out.println("Case " + flag + ":");System.out.println(a + " + " + b + " = " + sum);}}}