hdu 4190 Distributing Ballot Boxes

Distributing Ballot Boxes

Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 486 Accepted Submission(s): 250

Problem Description

Today, besides SWERC'11, another important event is taking place in Spain which rivals it in importance: General Elections. Every single resident of the country aged 18 or over is asked to vote in order to choose representatives for the Congress of Deputies and the Senate. You do not need to worry that all judges will suddenly run away from their supervising duties, as voting is not compulsory.
The administration has a number of ballot boxes, those used in past elections. Unfortunately, the person in charge of the distribution of boxes among cities was dismissed a few months ago due to nancial restraints. As a consequence, the assignment of boxes to cities and the lists of people that must vote in each of them is arguably not the best. Your task is to show how efficiently this task could have been done.
The only rule in the assignment of ballot boxes to cities is that every city must be assigned at least one box. Each person must vote in the box to which he/she has been previously assigned. Your goal is to obtain a distribution which minimizes the maximum number of people assigned to vote in one box.
In the first case of the sample input, two boxes go to the fi rst city and the rest to the second, and exactly 100,000 people are assigned to vote in each of the (huge!) boxes in the most efficient distribution. In the second case, 1,2,2 and 1 ballot boxes are assigned to the cities and 1,700 people from the third city will be called to vote in each of the two boxes of their village, making these boxes the most crowded of all in the optimal assignment.

Input

The fi rst line of each test case contains the integers N (1<=N<=500,000), the number of cities, and B(N<=B<=2,000,000), the number of ballot boxes. Each of the following N lines contains an integer a_i,(1<=a_i<=5,000,000), indicating the population of the i^th city.
A single blank line will be included after each case. The last line of the input will contain -1 -1 and should not be processed.

Output

For each case, your program should output a single integer, the maximum number of people assigned to one box in the most efficient assignment.

Sample Input

2 72000005000004 612026803400200-1 -1

Sample Output

1000001700

Source

SWERC 2011

Recommend

lcy

题目不难。但题目有点长。意思就是说。给出n个城市和n个城市的选民数。和b个投票箱。要求求出箱子的最小容量（每个箱子容量相同）。只有一个规则就是不同城市的选民

的选票不能放同一个箱子里。

#include <stdio.h>int city[5000010];//记录城市选民数int main(){    int n,b,i,top,bop,mid,pmax,c,ans;//pmax记录选民上限。即二分上限。    //ans记录满足条件的解    while(scanf("%d%d",&n,&b))    {        if(n==-1&&b==-1)            break;            pmax=0;//初始化        for(i=0;i<n;i++)            {                scanf("%d",&city[i]);                if(city[i]>pmax)                    pmax=city[i];            }            bop=0,top=pmax;            do            {                c=0;                mid=(top+bop)/2;                for(i=0;i<n;i++)                {                    if(city[i]%mid==0)                        c+=city[i]/mid;                    else                        c+=city[i]/mid+1;                }                if(c<=b)                   ans=mid,top=mid-1;                else                    bop=mid+1;            }while(top>=bop);            printf("%d\n",ans);    }    return 0;}