HDU4237:The Rascal Triangle

Problem Description

The Rascal Triangle definition is similar to that of the Pascal Triangle. The rows are numbered from the top starting with 0. Each row n contains n+1 numbers indexed from 0 to n. Using R(n,m) to indicte the index m item in the index n row:
  R(n,m) = 0 for n < 0 OR m < 0 OR m > n
The first and last numbers in each row(which are the same in the top row) are 1:
  R(n,0) = R(n,n) = 1
The interior values are determined by (UpLeftEntry*UpRightEntry+1)/UpEntry(see the parallelogram in the array below):
  R(n+1, m+1) = (R(n,m) * R(n,m+1) + 1)/R(n-1,m)

Write a program which computes R(n,m) theelement of therow of the Rascal Triangle.

 

Input

The first line of input contains a single integer P, (1 <= P <= 1000), which is the number of data sets that follow. Each data set is a single line of input consisting of 3 space separated decimal integers. The first integer is data set number, N. The second integer is row number n, and the third integer is the index m within the row of the entry for which you are to find R(n,m) the Rascal Triangle entry (0 <= m <= n <= 50,000).

 

Output

For each data set there is onr line of output. It contains the data set number, N, followed by a single space which is then followed by thr Rascal Triangle entry R(n,m) accurate to the integer value.

 

Sample Input

51 4 02 4 23 45678 123454 12345 98765 34567 11398

 

Sample Output

1 12 53 4114958864 243838455 264080263

 

/*一道规律题，通过找规律不难发现要求的数便是(x-y)*y+1我就不多说了,规律推出来就相当简单了*/#include <stdio.h>int main(){    int t,n;    __int64 x,y;    scanf("%d",&t);    while(t--)    {        scanf("%d%I64d%I64d",&n,&x,&y);        if(x == 0 || x == y || y == 0)        {            printf("%d 1\n",n);            continue;        }        printf("%d %I64d\n",n,(x-y)*y+1);    }    return 0;}