例题3-5

#include <iostream>#include <cmath>//c++的数学函数库using namespace std;int main(){float  a,b,c,x1,x2; cin>>a>>b>>c; x1=(-b+sqrt(b*b-4*a*c))/(2*a); x2=(-b-sqrt(b*b-4*a*c))/(2*a); cout<<"x1="<<x1<<endl; cout<<"x2="<<x2<<endl;//简单的一元二次方程求根 system("pause"); return 0;}