Struts2标签迭代数组汇总

1.一维数组

<s:iterator value="#request.headers" id="head" status="i">
  <td>${i.count}</td>
  <td>${head}</td>
</s:iterator>

   <select class="select1" tabindex="2" id="selectname3" name="selectname3" >
                             <s:iterator status="status" value="#request.select_acct"
            id="item" >
             <option value="item" />
              <s:property value='item' />
             </option>
            </s:iterator>
</select>

 

2.list

<s:iterator value= "{'1','2','3','4','5'}"  id= 'number' > 
    <s:property value= 'number' />
</s:iterator

3.map

<s:iterator value= "map"  id= "id"  status= "st" > 
     key : <s:property value= 'key' /> 
     value:<s:property vlaue= 'value' /> 
</s:iterator>

4：遍历数据栈.简单的List类，
List<Attr> 
class Attr{String attrName;String getAttrName(){return "123";}}

<s:iterator value= "label"  id= "id" > 
    <s:property value= "#id.attrName"  /> 
</s:iterator>

5：遍历2个list；
List<AttrName> attrN {color,size,style}
List<AttrValue> attrV {red,20,gay}
这2个list的元素是一一对应的，一个attrN对应一个attrV

< s:iterator   value = "%{attrN }"   id = "id"     status = "status" > 
 index    is :  < s:property   value = 'status.index' /> 
 attrName is :  < s:property   value = 'id' />  or  < s:property   value = '%{id}' />   
 attrName is :  < s:property   value = '%{attrV[#status.index]}' /> 
</ s:iterator > 

6.二维数组

struts2中二维数组的显示 
1、用两重循环的方法

<s:iterator id="data1" value="#request.data" status="d1">
<s:iterator id="data2" value="#request.data1" status="d2">
<s:property value="#data2"/>
</s:iterator>
</s:iterator>

2、用一重循环的方法

<s:iterator value="collection1" status="status">
<s:property value="collection1[#status.index][0]"/>
<s:property value="collection1[#status.index][1]"/>
</s:iterator>