HDU1088:Write a simple HTML Browser
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Problem Description
If you ever tried to read a html document on a Macintosh, you know how hard it is if no Netscape is installed.
Now, who can forget to install a HTML browser? This is very easy because most of the times you don't need one on a MAC because there is a Acrobate Reader which is native to MAC. But if you ever need one, what do you do?
Your task is to write a small html-browser. It should only display the content of the input-file and knows only the html commands (tags) <br> which is a linebreak and <hr> which is a horizontal ruler. Then you should treat all tabulators, spaces and newlines as one space and display the resulting text with no more than 80 characters on a line.
Now, who can forget to install a HTML browser? This is very easy because most of the times you don't need one on a MAC because there is a Acrobate Reader which is native to MAC. But if you ever need one, what do you do?
Your task is to write a small html-browser. It should only display the content of the input-file and knows only the html commands (tags) <br> which is a linebreak and <hr> which is a horizontal ruler. Then you should treat all tabulators, spaces and newlines as one space and display the resulting text with no more than 80 characters on a line.
Input
The input consists of a text you should display. This text consists of words and HTML tags separated by one or more spaces, tabulators or newlines.
A word is a sequence of letters, numbers and punctuation. For example, "abc,123" is one word, but "abc, 123" are two words, namely "abc," and "123". A word is always shorter than 81 characters and does not contain any '<' or '>'. All HTML tags are either <br> or <hr>.
A word is a sequence of letters, numbers and punctuation. For example, "abc,123" is one word, but "abc, 123" are two words, namely "abc," and "123". A word is always shorter than 81 characters and does not contain any '<' or '>'. All HTML tags are either <br> or <hr>.
Output
You should display the the resulting text using this rules:
. If you read a word in the input and the resulting line does not get longer than 80 chars, print it, else print it on a new line.
. If you read a <br> in the input, start a new line.
. If you read a <hr> in the input, start a new line unless you already are at the beginning of a line, display 80 characters of '-' and start a new line (again).
The last line is ended by a newline character.
. If you read a word in the input and the resulting line does not get longer than 80 chars, print it, else print it on a new line.
. If you read a <br> in the input, start a new line.
. If you read a <hr> in the input, start a new line unless you already are at the beginning of a line, display 80 characters of '-' and start a new line (again).
The last line is ended by a newline character.
Sample Input
Hallo, dies ist eine ziemlich lange Zeile, die in Htmlaber nicht umgebrochen wird.<br>Zwei <br> <br> produzieren zwei Newlines. Es gibt auch noch das tag <hr> was einen Trenner darstellt.Zwei <hr> <hr> produzieren zwei Horizontal Rulers.Achtung mehrere Leerzeichen irritierenHtml genauso wenig wiemehrere Leerzeilen.
Sample Output
Hallo, dies ist eine ziemlich lange Zeile, die in Html aber nicht umgebrochenwird.Zweiproduzieren zwei Newlines. Es gibt auch noch das tag--------------------------------------------------------------------------------was einen Trenner darstellt. Zwei----------------------------------------------------------------------------------------------------------------------------------------------------------------produzieren zwei Horizontal Rulers. Achtung mehrere Leerzeichen irritieren Htmlgenauso wenig wie mehrere Leerzeilen.
题意:1.出现<br>换行
2.出现<hr>输出‘-’
3.每一行的加上现在的单词如果长度超过80则换行,每个单词前留一个空格
4.结束时要输出换行
解法:知道了题意之后,就是很简单的题目了,注意处理就可以了
#include <stdio.h>#include <string.h>int main(){ char s[10000]; int len; int cnt = 0; while(~scanf("%s",s)) { if(!strcmp(s,"<br>")) { cnt = 0; printf("\n"); } else if(!strcmp(s,"<hr>")) { if(cnt) printf("\n--------------------------------------------------------------------------------\n"); else printf("--------------------------------------------------------------------------------\n"); cnt = 0; } else { int len = strlen(s); if(!cnt) { cnt = len; printf("%s",s); } else if(cnt+len+1>80) { cnt=len; printf("\n%s",s); } else { cnt+=len+1; printf(" %s",s); } } } printf("\n"); return 0;}
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