HDU3293：sort

Problem Description

As is known to all, long long ago sailormoon once was an association of fighters. Till now, sailormoon is also an association of girls. Owe to some unknown reasons, girls are necessary to fight for peace.
Their boss, lcy, wants to strengthen their ability, so he give them his precious collections---weapons for many years. Because these collections are really age-old, it is hard to recognize from one to another. So girls intend to sort them before they use. Each weapon has its name, origin and level of harmfulness ( level contains three ranks: wonderful, good, so-so).
In order to make it clear, girls want to sort like this:
firstly,sort according to the origin (sort by lexicographic order), if two or more have the same origin, they will be sorted together;
secondly, sort according ranks, wonderful is the best, good is next, the third is so-so;
thirdly, if two or more have same origin and rank, sort them according to the lexicographic order.

 

Input

Input contains multiply cases. Each case contains several lines. First line is an integer N(0<N<=500), representing the number of weapons. Then N lines follows. Each line represent a kind of weapon, and contains a set of strings representing name, origin and level of harmfulness. 
Each string will not exceed 20 characters.
Sure that same origin will not exist the same weapon.

 

Output

Please output your list after sorting (format according to sample, pay attention to the spaces,ten spaces need ^ ^).

 

Sample Input

5knife qizhou so-sogun qizhou wonderfulknife zhengzhou goodstick zhengzhou goodrope shengzhou so-so

 

Sample Output

Case 1qizhou:          gun wonderful          knife so-soshengzhou:          rope so-sozhengzhou:          knife good          stick good

 

 

一道简单的结构体排序

排序优先级

1：按持有者名字

2：按武器级别

3：按武器名字

水题

#include <stdio.h>#include <string.h>#include <algorithm>using namespace std;struct NODE{    char name[30];    char lv[30];    char ori[30];} girl[505];int cmp(NODE x,NODE y){    if(strcmp(x.ori,y.ori))        return strcmp(x.ori,y.ori)<0;    if(strcmp(x.lv,y.lv))    {        if(!strcmp(x.lv,"wonderful"))            return 1;        if(!strcmp(y.lv,"wonderful"))            return 0;        if(!strcmp(y.lv,"so-so"))            return 1;        if(!strcmp(x.lv,"so-so"))            return 0;    }    return strcmp(x.name,y.name)<0;}int main(){    int n,i,cas = 1;    while(~scanf("%d",&n))    {        for(i = 0; i<n; i++)            scanf("%s%s%s",girl[i].name,girl[i].ori,girl[i].lv);        printf("Case %d\n",cas++);        sort(girl,girl+n,cmp);        char s[30];        strcpy(s,girl[0].ori);        int flag = 1;        for(i = 0; i<n; i++)        {            if(flag)            {                printf("%s:\n",s);                flag = 0;            }            printf("          %s %s\n",girl[i].name,girl[i].lv);            if(strcmp(s,girl[i+1].ori))            {                strcpy(s,girl[i+1].ori);                flag = 1;            }        }    }    return 0;}