hdu1686之KMP
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Problem Description
The French author Georges Perec (1936–1982) once wrote a book, La disparition, without the letter 'e'. He was a member of the Oulipo group. A quote from the book:
Tout avait Pair normal, mais tout s’affirmait faux. Tout avait Fair normal, d’abord, puis surgissait l’inhumain, l’affolant. Il aurait voulu savoir où s’articulait l’association qui l’unissait au roman : stir son tapis, assaillant à tout instant son imagination, l’intuition d’un tabou, la vision d’un mal obscur, d’un quoi vacant, d’un non-dit : la vision, l’avision d’un oubli commandant tout, où s’abolissait la raison : tout avait l’air normal mais…
Perec would probably have scored high (or rather, low) in the following contest. People are asked to write a perhaps even meaningful text on some subject with as few occurrences of a given “word” as possible. Our task is to provide the jury with a program that counts these occurrences, in order to obtain a ranking of the competitors. These competitors often write very long texts with nonsense meaning; a sequence of 500,000 consecutive 'T's is not unusual. And they never use spaces.
So we want to quickly find out how often a word, i.e., a given string, occurs in a text. More formally: given the alphabet {'A', 'B', 'C', …, 'Z'} and two finite strings over that alphabet, a word W and a text T, count the number of occurrences of W in T. All the consecutive characters of W must exactly match consecutive characters of T. Occurrences may overlap.
Input
The first line of the input file contains a single number: the number of test cases to follow. Each test case has the following format:
One line with the word W, a string over {'A', 'B', 'C', …, 'Z'}, with 1 ≤ |W| ≤ 10,000 (here |W| denotes the length of the string W).
One line with the text T, a string over {'A', 'B', 'C', …, 'Z'}, with |W| ≤ |T| ≤ 1,000,000.
Output
For every test case in the input file, the output should contain a single number, on a single line: the number of occurrences of the word W in the text T.
Sample Input
3
BAPC
BAPC
AZA
AZAZAZA
VERDI
AVERDXIVYERDIAN
Sample Output
1
3
0
#include<iostream>#include<cstdio>#include<cstdlib>#include<cstring>#include<string>#include<queue>#include<algorithm>#include<map>#include<iomanip>#define INF 99999999using namespace std;const int MAX=1000000+10;char text[MAX];char word[10000+10];int next[10000+10];void get_next(char *a){//计算next,next会算到next[0...len] int i=0,j=-1,len=strlen(a);next[0]=-1;while(i<len){if(j == -1 || a[i] == a[j]){if(a[++i] != a[++j])next[i]=j;else next[i]=next[j];//一个优化,表示如果在kmp时a[i]和b[k]不匹配,那么a[i]=a[j],a[j]肯定和b[k]不匹配,所以用next[j]去匹配 }else j=next[j];}}int KMP(char *a,char *b){int i=0,j=0,lena=strlen(a),lenb=strlen(b),sum=0;while(i<=lena && j<lenb){if(i == -1 || a[i] == b[j])++i,++j;else i=next[i];if(i == lena)++sum;}return sum;}int main(){int n;cin>>n;while(n--){cin>>word>>text;get_next(word);cout<<KMP(word,text)<<endl;}return 0;}
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