UVaOJ10341 - Solve It

10341 - Solve It

Time limit: 3.000 seconds

Solve the equation:
        p*e^-x + q*sin(x) + r*cos(x) + s*tan(x) + t*x² + u = 0
        where 0 <= x <= 1.

Input

Input consists of multiple test cases and terminated by an EOF. Each test case consists of 6 integers in a single line: p, q, r, s, tand u (where 0 <= p,r <= 20 and -20 <= q,s,t <= 0). There will be maximum 2100 lines in the input file.

Output

For each set of input, there should be a line containing the value of x, correct upto 4 decimal places, or the string "No solution", whichever is applicable.

Sample Input

0 0 0 0 -2 1

1 0 0 0 -1 2

1 -1 1 -1 -1 1

Sample Output

0.7071

No solution

0.7554

#include <iostream>#include <cstdio>#include <cmath>using namespace std;double p, q, r, s, t, u;double f(double x) {    double temp;    temp = p * exp(-x) + q * sin(x) + r * cos(x) + s * tan(x) + t * x * x + u;    return temp;}int main() {    while (scanf("%lf%lf%lf%lf%lf%lf", &p, &q, &r, &s, &t, &u) != EOF) {        double high = 1.0, low = 0.0, mid;        for (int i = 0; i < 100; i ++) {            mid = (high + low) / 2;            if (f(mid) > 0) {                low = mid;            } else {                high = mid;            }        }        if (fabs(f(mid) - 0.0) < 1e-8) {            printf("%.4lf\n", mid);        } else {            printf("No solution\n");        }    }    return 0;}

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Mustaq Ahmed