10392 - Factoring Large Numbers

Problem F: Factoring Large Numbers

One of the central ideas behind much cryptography is that factoringlarge numbers is computationally intensive. In this context one mightuse a 100 digit number that was a product of two 50 digit primenumbers. Even with the fastest projected computers this factorizationwill take hundreds of years.

You don't have those computers available, but if you are clever youcan still factor fairly large numbers.

Input

The input will be a sequence of integer values, one per line,terminated by a negative number. The numbers will fit in gcc'slong long int datatype.You may assume that there will beat most one factor more than 1000000.

Output

Each positive number from the input must be factored and all factors(other than 1) printed out. The factors must be printed in ascendingorder with 4 leading spaces preceding a left justified number, andfollowed by a single blank line.

Sample Input

9012345678911899132545313912745267386521023-1

Sample Output

    2    3    3    5    1234567891    3    3    13    179    271    1381    2423    30971    411522630413

#include<stdio.h>#include<math.h>int main(){long long n,i;while(scanf("%lld",&n)&&n!=-1){for(i=2;i<sqrt((double)n);i++)while(n%i==0&&n!=1){printf("    %lld\n",i);n/=i;}if(n!=1) printf("    %lld\n",n);printf("\n");}return 0;}