The clone pattern

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 The clone pattern

 Jan 27, 2010 at 11:31pm
jsmith (5804)
In order to copy an object, you have to know at compile time the
object's type, because the type is the "name" of the copy constructor:

1234
void copy_me( const std::string& s ) {         std::string  s_copy( s );    std::string* p_s_copy = new std::string( s );}


I know at compile time that s has type "std::string" because it says
so in the parameter list. But what if type of s was a base class?

123456
class Base {};class Derived : public Base {};void copy_me( const Base& b ) {    Base b_copy( b );   // ????}


That doesn't quite work, because I can call copy_me() with a derived
class instance, in which case the function would want to instantiate
a Derived object, not a Base object. But at compile time there is
simply no way for me to know that. Indeed, I could even call copy_me()
with Base instances in one place, Derived in another, and something
else (derived from Base or Derived) in a third.

How can this problem be solved?

The clone pattern was implemented for exactly this reason. The
clone pattern looks like this:

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// Depending upon your needs, you might not require a base class// clonable concept.  It would only be needed if you need to store// clonable objects polymorphically.struct clonable {    virtual ~clonable() {}    virtual clonable* clone() const = 0;};class Base : public clonable {  public:     virtual Base* clone() const        { return new Base( *this ); }};class Derived : public Base {  public:     virtual Derived* clone() const        { return new Derived( *this ); }};


And now, copy_me looks like:

1234
void copy_me( const Base& b ) {    Base* clone = b.clone();    // delete clone;  };


And I've successfully invoked Base's copy constructor if the
"real type" of b is Base, and Derived's copy constructor if the
"real type" of b is Derived.

It is worth mentioning here that this technique exploits the fact that
the compiler does not consider the return type of the function when
determining whether or not a derived class virtual method has overridden
a base class one with the same name.
 Feb 28, 2010 at 3:21am
hamsterman (4538)
In order to copy an object, you have to know at compile time the
object's type
I think you can solve this problem in another way. If you know object's type at runtime you can copy it. For example:
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struct Base{    virtual int Type() const{        return 0;    }};struct Derived: Base{    virtual int Type() const{        return 1;    }};void copy_me(const Base& b){    Base* object = 0;    switch(b.Type()){        case 0://Base            object = new Base(b);            break;        case 1://Derived            object = new Derived((Derived&)b);            break;    }



c++ 中虚拟克隆(virtual clone)

又看了一遍more effective c++, 注意到以前没怎么记住的virtual clone技术。

复制代码
class Base {
public:
    
virtual Base* clone();
};

class Impl1 {
public:
    
virtual Impl1* clone(){return new Impl1(*this);}
};

class Impl2 {
public:
    
virtual Impl2* clone(){return new Impl2(*this;);}
};
复制代码

初一看没什么特别的。clone只是调用了拷贝构造函数。确实,在没有类层次结构的情况下,一个这样的clone()并不会比直接写拷贝构造有用。

奇特的是, 这里3个clone的返回类型是不一样的,但是编译器依然认为后两者是对基类clone()的实现!事实上不只是指针,返回引用也可以达到同样的效果。(题外话,虽然这里clone的语义显然只能返回指针,没人会返回一个局部对象的引用)。

 

 正是由于这种特性,使得以下实现成为可能:

 

复制代码
class Container {
public:
    Container(
const Container& c) {
        
for (List<Base*>::const_iterator it = c.items.begin(); it != c.items.end(); ++it) {
            items.push_back(
*it->clone());
    }
private:
    List
<Base*> items;
};
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 这样,每次调用的都是动态类型的clone函数,尽管他们返回的是不同类型,依然具备多态特性。(再扯一句题外话,这里容器里保存指针是很危险的,显然通过拷贝构造的Container对象必须在析构函数里负责delete他们。但是,倘若该Container有其他方式,比如某个push函数,保存指针,那么, container是否有权在析构是删除这些指针就是个问题了。 所以,当容器中不得不使用指针时,还是是最好用shared_ptr或auto_ptr)

 

 想起昨天在项目代码中也看到了一个clone()的实现。一看竟然没用到虚拟克隆。于是又这样的代码:

 

复制代码
Address::ptr
Address::create(
const sockaddr *name, socklen_t nameLen)
{
    MORDOR_ASSERT(name);
    Address::ptr result;
    
switch (name->sa_family) {
        
case AF_INET:
            result.reset(
new IPv4Address());
            MORDOR_ASSERT(nameLen 
<= result->nameLen());
            memcpy(result
->name(), name, nameLen);
            
break;
        
case AF_INET6:
            result.reset(
new IPv6Address());
            MORDOR_ASSERT(nameLen 
<= result->nameLen());
            memcpy(result
->name(), name, nameLen);
            
break;
        
default:
            result.reset(
new UnknownAddress(name->sa_family));
            MORDOR_ASSERT(nameLen 
<= result->nameLen());
            memcpy(result
->name(), name, nameLen);
            
break;
    }
    
return result;
}

Address::ptr
Address::clone()
{
    
return create(name(), nameLen());
}
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 显然,不足是基类的实现需要涉及所有存在的子类。而且,较真一点,时间效率也是问题。毕竟if else或者switch不如虚指针快。


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