32/64位系统int、long。。。所占字节

#include <stdio.h>int main(){        printf("char: %d\n",sizeof(char));        printf("char *: %d\n",sizeof(char *));        printf("short: %d\n",sizeof(short));        printf("short *: %d\n",sizeof(short *));        printf("int: %d\n",sizeof(int));        printf("int *: %d\n",sizeof(int *));        printf("long: %d\n",sizeof(long));        printf("long *: %d\n",sizeof(long *));}在一台x86_64系统上运行结果：char: 1char *: 8short: 2short *: 8int: 4int *: 8long: 8long *: 8在一台i386系统上运行结果：char: 1char *: 4short: 2short *: 4int: 4int *: 4long: 4long *: 41. sizeof返回的是byte值，1byte＝8bit；2. 指针类型表示的是内存寻址范围，所以在32位系统，8 * 4 = 32，而64位系统 8 * 8 = 64；这个是没错的；3. C99标准规定：sizeof(short) <= sizeof(int) <= sizeof(long).