B. Little Elephant and Numbers

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

The Little Elephant loves numbers.

He has a positive integer x. The Little Elephant wants to find the number of positive integers d, such that d is the divisor of x, and x andd have at least one common (the same) digit in their decimal representations.

Help the Little Elephant to find the described number.

Input

A single line contains a single integer x (1 ≤ x ≤ 109).

Output

In a single line print an integer — the answer to the problem.

Sample test(s)

input

1

output

1

input

10

output

2

解题说明：此题是统计能被x整除并且和x至少存在一位数相同的数字个数。可以先把x中所包含的数字找出来，用一个大小为10的数组标记即可，然后从1到根号x开始遍历，针对每一个数字判断能否被x整除，如果整除就判断是否存在数字相同的位，可以写一个子函数判断数字是否相同。注意由于遍历区间是1到根号x，故需要判断大于根号x到x之间的情况，此时只需要判断x/i的情况即可，否则会少计算一部分数字。

#include<iostream>#include<map>#include<string>#include<algorithm>#include<cstdio>#include<cmath>using namespace std;int arr[10];int ans = 0;void check_common(int i){    while(i>0){if(arr[i%10]==1){ans++;break;}i = i/10;    }}int main(){int x,n,b=0,i;for(i=0;i<10;i++){arr[i] = 0;}cin >> x;n = x;while(n>=1){arr[n%10] = 1;n = n/10;}if(x==1){ans = 1;}else{for(i=1;i*i<=x;i++){if(x%i==0){ check_common(i);if(x/i!=i){check_common(x/i);}}}}cout << ans<<endl;return 0;}