Java http get/post 传递json参数问题

来源：互联网发布：java构造函数重载定义编辑：程序博客网时间：2024/05/16 18:38

今天做项目的时候，需要向服务器接口传递 json参数，使用 apache 的 httpclient，当时没有对参数做特殊处理直接提交了，结果运行时报错了，如下：

06-06 10:05:40.683: W/System.err(15573): java.lang.IllegalArgumentException: Illegal character in query at index 40: http://xxxxx.com/detail/?info={"type":"1","shopid":"f436701fd5c0423db53a8047894ca4e1","fields":{"name":true,"tel":true,"scores":true,"intro":true}}06-06 10:05:40.753: W/System.err(15573): at java.net.URI.create(URI.java:727)06-06 10:05:40.753: W/System.err(15573): at org.apache.http.client.methods.HttpGet.<init>(HttpGet.java:75)06-06 10:05:40.753: W/System.err(15573): at com.yulore.sdktest.http.NetUtil.get(NetUtil.java:106)06-06 10:05:40.777: W/System.err(15573): at com.yulore.sdktest.http.BaseTask.run(BaseTask.java:25)06-06 10:05:40.777: W/System.err(15573): at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1076)06-06 10:05:40.777: W/System.err(15573): at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:569)06-06 10:05:40.777: W/System.err(15573): at java.lang.Thread.run(Thread.java:856)

后来在网上查资料找到原因了：HttpGet或 HttpPost都不能传包含 " 、“{"、"}"这样的参数，需要对特殊字符进行转义，把 " 转成%22，把 { 转成%7b，把 } 转成%7d

RequestVo reqVo = new RequestVo();reqVo.context = getApplicationContext();StringBuffer sb = new StringBuffer();sb.append("?info={\"type\":\"1\",");sb.append("\"shopid\":\"" + shopId + "\",");sb.append("\"fields\":{\"name\":true,");sb.append("\"address\":true,");sb.append("\"tel\":true,");sb.append("\"scores\":true,");sb.append("\"intro\":true}}");String param = sb.toString().replace("\"", "%22").replace("{", "%7b").replace("}", "%7d");//特殊字符进行转义reqVo.requestUrl = getString(R.string.detail_api).concat(param);reqVo.jsonParser = new ShopParser();BaseTask task = new BaseTask(getApplicationContext(), reqVo,handler);ThreadPoolManager.getInstance().addTask(task);

注意：参数里面如果有空格的话，也需要转义，否则会有问题。