杭电ACM 1002

看清格式描述很重要：

For each test case, you should output two lines. The first line is "Case #:", # means the number of the test case. The second line is the an equation "A + B = Sum", Sum means the result of A + B. Note there are some spaces int the equation. Output a blank line between two test cases.

如1 + 2 = 3;有几个空格，两个测试用例之间输入一个空行；

本人就是改了个presentation error改了好久......

C++:

#include<iostream>#include<string>#include<vector>using namespace std;bool check(string a,string b);void StringPlus(string a,string b);int main(){int T=0;string a;string b;cin>>T;if(T>20||T<1)return 0;int count=1;while(T!=0&&cin>>a>>b&&!cin.fail()){bool Istrue=check(a,b);if(Istrue){cout<<"Case "<<count<<":"<<endl;StringPlus(a,b);cout<<endl;}T--;count++;if(T>0)cout<<endl;}int Pause;cin>>Pause;return 0;}bool check(string a,string b){int i=0;int j=0;for(i;i<a.length();i++){if(a[i]<'0'||a[i]>'9')break;}for(j;j<b.length();j++){if(b[j]<'0'||b[j]>'9')break;}if(i<a.length()||j<b.length())return false;return true;}void StringPlus(string a,string b){vector<char> temp;string L,S;if(a.length() >b.length() ){L=a;S=b;}else{L=b;S=a;}int i,j;int temp1,temp2;char temp3;int add=0;//进位int yushu;for(i=S.length()-1,j=L.length ()-1;i>=0;i--,j--){temp1=S[i]-48;temp2=L[j]-48;//cout<<"temp1 temp2 add:"<<temp1<<" "<<temp2<<" "<<add<<endl;yushu=add+temp1+temp2-10;//cout<<"yushu:"<<yushu<<endl;if(yushu>=0)add=1;else {yushu+=10;add=0;}//此处add置0很重要

//cout<<"yushu"<<yushu<<endl;temp3=yushu+48;temp.push_back(temp3);}for(j;j>=0;j--){  temp2=L[j]-48;  yushu=add+temp2-10;  if(yushu>=0)add=1;  else {yushu+=10;add=0;}//此处add置0很重要  temp3=yushu+48;  temp.push_back(temp3);}if(add==1){temp3=add+48;temp.push_back(temp3);}cout<<a<<" + "<<b<<" = ";for(int k=temp.size()-1;k>=0;k--){ cout<<temp[k];}}

 

 

C：

#include<stdio.h>#include<stdlib.h>#include<string.h>void change(char *a){    int l,i;    char temp;    l=strlen(a);    for(i=0;i<l/2;i++)    {        temp=a[i];        a[i]=a[l-1-i];        a[l-1-i]=temp;    }}void Add(char *a,char *b){    int lena,lenb,i,max;    int aa[1001],bb[1001];    lena=strlen(a);    lenb=strlen(b);    max=(lena>lenb?lena:lenb);    memset(aa,0,sizeof(aa));    memset(bb,0,sizeof(bb));    for(i=0;i<lena;i++)        aa[i]=a[i]-'0';    for(i=0;i<lenb;i++)        bb[i]=b[i]-'0';    for(i=0;i<=max;i++)    {        aa[i]=aa[i]+bb[i];        if(aa[i]>9)        {            aa[i]-=10;            aa[i+1]+=1;        }    }    if(aa[max]>0)        printf("%d",aa[max]);    for(i=max-1;i>=0;i--)    {        printf("%d",aa[i]);    }    printf("\n");}int main(){    char a[1001],b[1001];    int n,i;    scanf("%d",&n);    for(i=1;i<=n;i++)    {        scanf("%s%s",a,b);        printf("Case %d:\n",i);        printf("%s + %s = ",a,b);        change(a);        change(b);        Add(a,b);        if(i<n)            printf("\n");    }    //system("pause");    return 0;}