sql常用面试题

--1、查询"1"课程比"2"课程成绩高的所有学生的学号；select d.S# from (select b.S#,b.score as b_score,c.score as c_score from(select S#,score from Sc WHERE C#=1) b inner join(select S#,score  from Sc WHERE C#=2) c on b.S#=c.S#) dwhere d.b_score>d.c_score--2、查询平均成绩大于60分的学号和平均成绩；select S#,AVG(score) from Sc Group by S# having AVG(score)>60--3、查询所有同学的学号、姓名、选课数、总成绩；SELECT a.*,CASE WHEN Num IS null THEN 0 ELSE Num END AS '课程总数',CASE WHEN Total IS NULL THEN 0ELSE Total END AS '总成绩'FROM(select S#,Sname from Student) a left join (select S#,COUNT(*) AS Num,SUM(score) as Total from Sc Group BY S#) b --找所有同学的选课数和总成绩on a.S#=b.S#--4、查询姓"李"的老师个数；select COUNT(*) from Teacher where Tname LIKE '李%'--5、查询没学过"叶平"老师课的同学的学号、姓名；--(把学过学生的学号先找出来)SELECT d.* FROM Student d left join (select distinct a.S# from Sc a inner join (select C# from Course where T#=(select T# from Teacher where Tname='叶平')) b on a.C#=b.C#) c on c.S#=d.S# where c.S# is null--6、查询学过"1"并且也学过编号"2"课程的同学的学号、姓名；select b.* from(select Distinct S# from Sc where C#=1 or C#=2 group by S# having COUNT(*)=2) a inner join (select S#,Sname from Student) b on a.S#=b.S#--7、查询学过"叶平"老师所交的所有课程的同学的学号、姓名；select a.S# from(select * from Sc) a inner join (select C# from Course where T#=(select T# from Teacher where Tname='叶平')) b on a.C#=b.C# group by a.S# having COUNT(*)=(select COUNT(*) from Course where T#=(select T# from Teacher where Tname='叶平'))--9、查询所有课程成绩小于60的同学的学号、姓名；select b.* from(select distinct S# from Sc WHERE score<60) a inner join(select S#,Sname from Student) b on a.S#=b.S#--10、查询没有学所有课的同学的学号、姓名；select a.* from(select S#,Sname from Student) a left join(select S# from Sc group by S# having COUNT(*)=(select COUNT(*) from Course)) bon a.S#=b.S# where b.S# is null--11、查询至少有一门课与"张三"的同学相同的同学的学号和姓名；select distinct a.S#,c.Sname from(select S#,C# from Sc where S#!=(select S# from Student where Sname='张三')) a inner join(select C# from Sc where S#=(select S# from Student where Sname='张三')) b on a.C#=b.C# inner join (select S#,Sname from Student) c on a.S#=c.S#--12、查询学过学号为"1"同学所有课的其他同学学号和姓名；select d.* from(select S#  from(select C# from Sc WHERE S#=1) a inner join(select * from Sc where S#!=1) b on a.C#=b.C# group by b.S# having COUNT(*)=(select COUNT(*) from Sc WHERE S#=1)) c inner join(select  S#,Sname from Student) d on c.S#=d.S#