FatMouse's Speed-HDU-动态规划

FatMouse's Speed

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6929    Accepted Submission(s): 3028
Special Judge

Problem Description

FatMouse believes that the fatter a mouse is, the faster it runs. To disprove this, you want to take the data on a collection of mice and put as large a subset of this data as possible into a sequence so that the weights are increasing, but the speeds are decreasing.

 

Input

Input contains data for a bunch of mice, one mouse per line, terminated by end of file.

The data for a particular mouse will consist of a pair of integers: the first representing its size in grams and the second representing its speed in centimeters per second. Both integers are between 1 and 10000. The data in each test case will contain information for at most 1000 mice.

Two mice may have the same weight, the same speed, or even the same weight and speed. 

 

Output

Your program should output a sequence of lines of data; the first line should contain a number n; the remaining n lines should each contain a single positive integer (each one representing a mouse). If these n integers are m[1], m[2],..., m[n] then it must be the case that 

W[m[1]] < W[m[2]] < ... < W[m[n]]

and 

S[m[1]] > S[m[2]] > ... > S[m[n]]

In order for the answer to be correct, n should be as large as possible.
All inequalities are strict: weights must be strictly increasing, and speeds must be strictly decreasing. There may be many correct outputs for a given input, your program only needs to find one. 

 

Sample Input

6008 13006000 2100500 20001000 40001100 30006000 20008000 14006000 12002000 1900

 

Sample Output

44597

 

先按体重 或 速度排序。

之后就是求其中的最大单调序列的长度了，这个是个很常见的问题了。

#include <iostream>#include <algorithm>#include <stdio.h>#include <string.h>using namespace std;int opt[1001], trace[1001], ans[1001];struct Node{int w,p,index;};bool cmp(const Node & a, const Node & b){return a.w < b.w;}Node mice[1001];int main() {//freopen("in.txt", "r", stdin);int k = 0;while(cin >> mice[k].w >> mice[k].p){mice[k].index = k+1;k++;}memset(opt, 0 ,sizeof(opt));memset(trace, 0 ,sizeof(trace));sort(mice, mice+k, cmp);int tmax = 0,index;for(int i=1; i<k; i++){for(int j=0; j<i; j++){if(mice[i].p  < mice[j].p && mice[i].w > mice[j].w){if(opt[j] + 1 > opt[i]){opt[i] = opt[j] + 1;//trace[i] = mice[j].index;trace[i] = j;}}}if(opt[i] > tmax){tmax = opt[i];index = i;}}for(int i=tmax; i>=0; i--){ans[i] = mice[index].index;index = trace[index];}//for(int i=0; i<k; i++)//cout << opt[i] << " ";//cout << endl;//for(int i=0; i<k; i++)//cout << trace[i] << " ";//cout << endl;cout <<tmax+1 << endl;for(int i=0; i<=tmax; i++)cout << ans[i] << endl;return 0;}