Ajax.BeginForm返回方法OnSuccess

Ajax.BeginForm返回方法OnSuccess = "refresh"

在后台Controller里return Content("OK");

前台：

    function refresh(e) {
        if (e.toString() == "OK") {
            alert("评论成功！");
            window.location.href = window.location.href;
        }
        else {
            window.location.href = "../../UserInfo/Login?backurl=" + window.location.href;
        }
    }