httpclient通过POST来上传文件，而不是通过流的形式，并在服务端进行解析(通过httpmime.jar来操作)

1. 首先需要对应的JAR包 导入 httpmime-4.1.1.jar。

[java] view plaincopyprint?

1. package url;  
2.   
3. import io.IoStreamUtil;  
4.   
5. import java.io.File;  
6. import java.io.IOException;  
7. import java.io.InputStream;  
8.   
9. import org.apache.http.HttpEntity;  
10. import org.apache.http.HttpResponse;  
11. import org.apache.http.client.ClientProtocolException;  
12. import org.apache.http.client.HttpClient;  
13. import org.apache.http.client.methods.HttpPost;  
14. import org.apache.http.entity.mime.MultipartEntity;  
15. import org.apache.http.entity.mime.content.FileBody;  
16. import org.apache.http.entity.mime.content.StringBody;  
17. import org.apache.http.impl.client.DefaultHttpClient;  
18.   
19. /** 
20.  * httpclient上传文件 
21.  * @author linwei 
22.  * 
23.  */  
24. public class MultipartEntityUtil {  
25.   
26.     public static String postFile(File file,String url) throws ClientProtocolException, IOException {  
27.   
28.         FileBody bin = null;  
29.         HttpClient httpclient = new DefaultHttpClient();  
30.         HttpPost httppost = new HttpPost(url);  
31.         if(file != null) {  
32.             bin = new FileBody(file);  
33.         }  
34.   
35.         StringBody username = new StringBody("13696900475");  
36.         StringBody password = new StringBody("13696900475");  

package url;import io.IoStreamUtil;import java.io.File;import java.io.IOException;import java.io.InputStream;import org.apache.http.HttpEntity;import org.apache.http.HttpResponse;import org.apache.http.client.ClientProtocolException;import org.apache.http.client.HttpClient;import org.apache.http.client.methods.HttpPost;import org.apache.http.entity.mime.MultipartEntity;import org.apache.http.entity.mime.content.FileBody;import org.apache.http.entity.mime.content.StringBody;import org.apache.http.impl.client.DefaultHttpClient;/** * httpclient上传文件 * @author linwei * */public class MultipartEntityUtil {public static String postFile(File file,String url) throws ClientProtocolException, IOException {FileBody bin = null;HttpClient httpclient = new DefaultHttpClient();HttpPost httppost = new HttpPost(url);if(file != null) {bin = new FileBody(file);}StringBody username = new StringBody("13696900475");StringBody password = new StringBody("13696900475");

[java] view plaincopyprint?

1. //请记住，这边传递汉字会出现乱码，解决方法如下,设置好编码格式就好  

                //请记住，这边传递汉字会出现乱码，解决方法如下,设置好编码格式就好

[java] view plaincopyprint?

1.                //new StringBody("汉字",Charset.forName("UTF-8")));    
2.       
3.     MultipartEntity reqEntity = new MultipartEntity();  
4.     reqEntity.addPart("username", username);  
5.     reqEntity.addPart("password", password);  
6.     reqEntity.addPart("data", bin);  
7.       
8.     httppost.setEntity(reqEntity);  
9.     System.out.println("执行: " + httppost.getRequestLine());  
10.       
11.     HttpResponse response = httpclient.execute(httppost);  
12.     System.out.println("statusCode is " + response.getStatusLine().getStatusCode());  
13.     HttpEntity resEntity = response.getEntity();  
14.     System.out.println("----------------------------------------");  
15.     System.out.println(response.getStatusLine());  
16.     if (resEntity != null) {  
17.       System.out.println("返回长度: " + resEntity.getContentLength());  
18.       System.out.println("返回类型: " + resEntity.getContentType());  
19.       InputStream in = resEntity.getContent();  
20.       System.out.println("in is " + in);  
21.       System.out.println(IoStreamUtil.getStringFromInputStream(in));  
22.     }  
23.     if (resEntity != null) {  
24.       resEntity.consumeContent();  
25.     }  
26.     return null;  
27. }  
28.   
29. public static void main(String[] args) throws ClientProtocolException, IOException {  
30.   
31.     File file = new File("d:/rss.xml");  
32.     String url = "http://localhost:8080/webtest/servlet/URLTest";  
33.     postFile(file,url);  
34. }  
35.   

                //new StringBody("汉字",Charset.forName("UTF-8")));      MultipartEntity reqEntity = new MultipartEntity();    reqEntity.addPart("username", username);    reqEntity.addPart("password", password);    reqEntity.addPart("data", bin);        httppost.setEntity(reqEntity);    System.out.println("执行: " + httppost.getRequestLine());        HttpResponse response = httpclient.execute(httppost);    System.out.println("statusCode is " + response.getStatusLine().getStatusCode());    HttpEntity resEntity = response.getEntity();    System.out.println("----------------------------------------");    System.out.println(response.getStatusLine());    if (resEntity != null) {      System.out.println("返回长度: " + resEntity.getContentLength());      System.out.println("返回类型: " + resEntity.getContentType());      InputStream in = resEntity.getContent();      System.out.println("in is " + in);      System.out.println(IoStreamUtil.getStringFromInputStream(in));    }    if (resEntity != null) {      resEntity.consumeContent();    }return null;}public static void main(String[] args) throws ClientProtocolException, IOException {File file = new File("d:/rss.xml");String url = "http://localhost:8080/webtest/servlet/URLTest";postFile(file,url);}}

2. 服务端的接收解析代码(同样的，服务端也需要导入上面提到的JAR包) (特别注释：在servlet中直接获取的request是可以正常解析的，但是，在ACTION中获取的request则是通过ACTION内部的类进行了封装，因此，在ACTION中执行以下代码，upload.parseRequest(request)方法执行返回的是空的，暂没找到解决办法。)

 

[java] view plaincopyprint?

1.                 //commons-fileupload.jar  commons-io   
2. <SPAN style="WHITE-SPACE: pre">     </SPAN>request.setCharacterEncoding("UTF-8");  
3. <SPAN style="WHITE-SPACE: pre">     </SPAN>boolean isMultipart = ServletFileUpload.isMultipartContent(request);  
4. <SPAN style="WHITE-SPACE: pre">     </SPAN>  
5. <SPAN style="WHITE-SPACE: pre">     </SPAN>if (isMultipart) {    
6.             FileItemFactory factory = new DiskFileItemFactory();    
7.             ServletFileUpload upload = new ServletFileUpload(factory);    
8.             try {     
9.                 List items = upload.parseRequest(request);    
10.                 Iterator iter = items.iterator();    
11.                 while (iter.hasNext()) {    
12.                     FileItem item = (FileItem) iter.next();    
13.                     if (item.isFormField()) {    
14.                         //普通文本信息处理     
15.                         String paramName = item.getFieldName();    
16.                         String paramValue = item.getString();    
17.                         System.out.println(paramName + ":" + paramValue);    
18.                     } else {    
19.                         //上传文件信息处理    
20.                         String fileName = item.getName();    
21.                         byte[] data = item.get();    
22.                         String filePath = "d:/ssssss.txt";    
23.                         FileOutputStream fos = new FileOutputStream(filePath);    
24.                         fos.write(data);    
25.                         fos.close();    
26.                     }    
27.                 }     
28.             } catch (FileUploadException e) {    
29.                 e.printStackTrace();    
30.             }    
31.         }