考察二进制向int或uint转换时的最高位处理

//最高位的变化#include "stdio.h"#include "cstring"using namespace std;int  main(){    unsigned short A = 10;//2B,16bits,0000 0000 0000 1010    //若unsigned short输出，~A = 1111 1111 1111 0101 = 2^16 - 11 = 1024*64-11            printf("0xFFF5 = %d\n", 0xFFF5);    printf("0xFFFFFFF5 = %d\n", 0xFFFFFFF5);    printf("0xFFFFFFF5 = %u\n", 0xFFFFFFF5);//Uint输出，4B    int s = sizeof(unsigned short);        printf("sizeof(unsigned short) = %d\n", s);        printf("~A = %u\n", ~A); //Uint输出，4B        char c=128; //128 二进制 1000 0000 ，    printf("c=%c\n",c);//单个字符输出，1B 不是128    //printf("c=%s\n",c);//error        int ss = sizeof(char);        printf("sizeof(char) = %d\n", ss);        printf("c=%d\n",c);//int输出，-128    //单字节二进制 1000 0000，转化为4B---1111 1111 1111 1111 1111 1111 1000 0000    //负数，取反加1---1000,0000,0000,0000,0000,0000,0111,1111+1  printf("c=%u\n",c);//c=4294967168   printf("c=%u\n",0xFFFFFF80);     return 0;}