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来源:互联网 发布:js求100以内相加的和 编辑:程序博客网 时间:2024/04/30 13:34

#include<stdio.h>
int main()
{
 int n,i,str[100],sum;
 int a1[100],a2[100],b1[100],b2[100],c1[100],c2[100],d1[100],d2[100],e1[100],e2[100],f[100];
 while((scanf("%d",&n))!=EOF,n)
 {
        for(i=0;i<n;i++)
  {
   scanf("%d",&str[i]);
  }
  sum=0;
  for(i=0;i<n;i++)
  {
   a1[i]=str[i]/100;
   a2[i]=str[i]%100;
   b1[i]=a2[i]/50;
   b2[i]=a2[i]%50;
   c1[i]=b2[i]/10;
   c2[i]=b2[i]%10;
   d1[i]=c2[i]/5;
   d2[i]=c2[i]%5;
   e1[i]=d2[i]/2;
   e2[i]=d2[i]%2;
            f[i]=e2[i]/1;
   sum+=a1[i]+b1[i]+c1[i]+d1[i]+e1[i]+f[i];
  }
  printf("%d\n",sum);
 }
}

//死算的方法!

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