Eming

     Emingis a contest hold by WHUACM training team. The aim is to select new members ofthe team.

   Usually, the first problem is a very simpleproblem such as “a+b problem”. But this time, Xioumu is tired of this kind of problem,he decide to solve “a and b problem”.

   Give you the result of a + b and a^2 – b^2,please output the result of a and b.

 

   Input

   There are several test cases. For each casethere are two double numbers indicating a+b and a^2-b^2. You may assume that a+bwill not be zero.

 

   Output

   For each case please output the result of aand b in one line, rounded to 2 decimal places.

 

   SampleInput

   3 -3

 

   SampleOutput

   1.00 2.00

试题分析：这道题意思是给了a+b和a^2 – b^2的值，要求a和b的值，如果直接暴力枚举的话肯定会超时，所以运用数学上的运算就可以了，给（a+b）平方再加上 a^2 – b^2，再除以2*（a+b），得出a的值，则可得b的值。下面是代码：

#include <iostream>#include <cstdio>#include <cstring>#include <cmath>#include <cstdlib>using namespace std;int main() {    double A, B, C;    while(scanf("%lf%lf", &A, &B) == 2) {        C = B / A;        printf("%.2lf %.2lf\n", (A + C) * 0.5, (A - C) * 0.5);    }    return 0;}