UVA 133 Power of Cryptography 。。。其实很简单
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UVA 133 Power of Cryptography
一眼看上去像是高精度。 其实仔细看题目,只到100多位。完全可以用double来做,最后强制类型转换成int就可以了
代码就几行。 非常水。。。。
#include <stdio.h>#include <string.h>#include <math.h>double n, p;double k;int main(){ while (scanf("%lf%lf", &n, &p)!= EOF) {printf("%d\n", int (pow(p, 1/n) + 0.5)); } return 0;}
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